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13. Heights(cm) and weights(kg) are measured for 100 randomly selected adultmales, and range from heights of137to 190cm and weights of 39to 150kg. Let the predictor

13. Heights(cm) and weights(kg) are measured for 100 randomly selected adultmales, and range from heights of137to 190cm and weights of 39to 150kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x=167.16cm,y=81.42kg,r=0.251,P-value=0.012,and<="" path="">y=106+1.06x.Find the best predicted value of<="" path="">y(weight) given an adult male who is150cm tall. Use a 0.05

significance level.

Question content area bottomPart 1

The best predicted value of<="" path="">yfor an adult male who is 150cm tall is

enter your response herekg.

(Round to two decimal places asneeded.)

14. In a Leichtman Research Group survey of900TVhouseholds,74.6%of them had at least oneInternet-connected TV device(for example, SmartTV, standalone streamingdevice, connected video gameconsole). A marketing executive wants to convey high penetration ofInternet-connected TVdevices, so he makes the claim that the percentage of all homes with at least oneInternet-connected TV device is equal to80%.Test that claim using a0.10significance level. Use theP-value method. Use the normaldistribution as an approximation to the binomial distribution.

Question content area bottomPart 1

Let p denote the population proportion of all homes with at least oneInternet-connected TV device. Identify the null and alternative hypotheses.

H0:

p

less than<

not equals

equals=

greater than>

enter your response here

H1:

p

not equals

less than<

equals=

greater than>

enter your response here

(Type integers or decimals. Do notround.)

Part 2

Identify the test statistic.

z=enter your response here

(Round to two decimal places asneeded.)

Part 3

Identify theP-value.

P-value=enter your response here

(Round to three decimal places asneeded.)

Part 4

State the conclusion about the nullhypothesis, as well as the final conclusion that addresses the original claim.

Fail to reject

Accept

Reject

the null hypothesis. There

is

is not

sufficient evidence to

support

warrant rejection of

the claim that the percentage of all homes with at least oneInternet-connected TV device is equal to80%.

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