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#13 mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=618060631&questionld=19&flushed=false&cld=6833174¢erwin=yes Paused Update : Math-K300 Spring 2022 Online Kierstyn Cochran 03/27/22 3:55 PM E Homework: Section 6.4 Confidence Intervals for Question 13, 6.4.20-T HW

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mylab.pearson.com/Student/PlayerHomework.aspx?homeworkld=618060631&questionld=19&flushed=false&cld=6833174¢erwin=yes Paused Update : Math-K300 Spring 2022 Online Kierstyn Cochran 03/27/22 3:55 PM E Homework: Section 6.4 Confidence Intervals for Question 13, 6.4.20-T HW Score: 60.23%, 13.25 of 22 points Points: 0 of 1 Save Variance and Part 3 of 4 As part of a survey, a marketing representative asks a random sample of 27 business owners how much they would be willing to pay for a website for their company. She finds that the sample standard deviation is $3515. Assume the sample is taken from a normally distributed population. Construct 99% confidence intervals for (a) the population variance of and (b) the population standard deviation or. Interpret the results. (a) The confidence interval for the population variance is ( 6652239 , 28783962 ) (Round to the nearest integer as needed.) Interpret the results. Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to the nearest integer as needed.) O A. With 1% confidence, you can say that the population variance is less than O B. With 1% confidence, you can say that the population variance is between and C. With 99% confidence, you can say that the population variance is between O D. With 99% confidence, you can say that the population variance is greater than 6652239 and 28783962 (b) The confidence interval for the population standard deviation is (].) (Round to the nearest integer as needed.)

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