(13%) Problem 1: A block having a mass of m = 18.5 kg is suspended via two cables as shown in the figure. The angles shown in the figure are as follows: a = 13 and B = 35. We will label the tension in Cable 1 as 71 and the tension in Cable 2 as T2. - Cable 1 Cable 2 -.--.-. m y -X Otheexpertta.com 20% Part (a) From the images below, choose the correct free body diagram. Correct! * 20% Part (b) Write an expression for the sum of forces in the x direction in terms of 71, 72, m, g, a, and B. Use the specified coordinate system. Efx = - T1 sin(a) + To sin(B) -| Grade Summary Deductions 0% Potential 100% cos(a) cos(B) sin(a() ( 7 8 9 HOME Submissions sin(3) tan(o() tan(B) 4 5 6 Attempts remaining: 985 d g h 1 2 3 (0% per attempt) m S 0 END detailed view T1 NO BACKSPA DEL CLEAR I 0% 0% Submit Hint Feedback I give up! W N 0% Hints: 3 for a 0% deduction. Hints remaining: 0 Feedback: 10 for a 0% deduction You need to break each force down into the components Check your trigonometry and refer to the free body and consider only components in the x direction. Be very diagram: angles P and a are measured from different careful to look where the angles are measured from reference points. -Not all angles are measured from horizontal, which affects how sin() and cos() relate to the vertical and horizontal components. -The two tensions should be the only forces acting in the x- direction and the x components of these forces should balance & 20% Part (c) Write an expression for the sum of forces in the y direction in terms of T1, T2, m, g, a, and B. Use the specified coordinate system. 4 20% Part (d) Solve for the numeric value of 71, in newtons. & 20% Part (e) Solve for the numeric value of 72, in newtons