(13%) Problem 2: In this problem you will measure the gravitational constant in a series of "observational experiments," making use of Newton's law of gravitation and second law of motion as well as Kepler's third law of planetary motion 20% Part (a) Newton measured the centripetal acceleration of the moon in its orbit around Earth by comparing the force Earth exerts on the moon with the force Earth exerts on an apple. He obtained a value of ac = 2.7x10-> m/s. If Newton had taken the mass of Earth to be ME = 6.03x1024 kg and the mean distance between the centers of Earth and the moon to be RME = 3.8x108 m, what value would he have obtained for the gravitational constant, in units of N. m2/kg2? G=6.46 * 10-11 G = 6.46E-11 \\ Correct! * 20% Part (b) Since measuring the centripetal acceleration of an orbiting body is rather difficult, an alternative approach is to use the body's rotational period instead. Enter an expression for the gravitational constant, in terms of the distance between Earth and the moon, RME, Earth's mass,ME, and the moon's period of rotation around Earth, T. G = (TRME/ME2 ) X Attempts Remain 20% Part (c) Using the expression you entered in part (b) and taking the rotational period of the moon to be T= 27.1 days, what value would Newton have calculated for the gravitation constant, in units of N. m-/kg-? Take ME = 6.03x1024 kg and RME = 3.8x108 m. G = Grade Summary Deductions 0% Potential 100% sin() cos() tan( 8 9 HOME Submissions cotan() asin( acos() 5 Attempts remaining: atan( acotan() sinh() 2 (0% per attempt) cosh() tanh() cotanh() END detailed view ODegrees O Radians BACKSPAC CLEAR Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback. Submission History All Date times are displayed in Pacific Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 4 20% Part (d) The gravitational constant may also be calculated by analyzing the motion of a rocket. Suppose a rocket is launched vertically from the surface or Earth at an initial speed of vi. Its initial distance from the center of Earth is Ri, the radius of Earth. Its peak distance, where its speed is momentarily zero is, is Rf. For simplicity, ignore air resistance and Earth's rotation. Enter an expression for the gravitational constant, in terms of vi, Ri, Rf, and ME. 4 20% Part (e) Suppose a rocket is launched as described in part (d) with an initial speed of vi = 503 m/s and attains a peak altitude of H = 13.3 km above the surface of Earth. Taking ME = 6.03x102# kg and Ri = 6.3x10 m, what is the measured value of the gravitational constant, in units of N. m-/kg2