(13%) Problem 7: On a one lane road, a person driving a car at v = 61 mi/h suddenly notices a truck d= 0.55 mi in front of him. That truck is moving in the same direction at v2 = 31 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v during time interval At. The smallest acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. Refer to the figure below. V1 d V2 Enter an expression for the acceleration of the car, a, in terms of v, v2, and At. A 11% Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax2, traveled by the truck during the time interval At. A 11% Part (b) Enter an expression for the distance, Ax, traveled by the car in terms of v, v2 and a. A 11% Part (c) = A 11% Part (d) A 11% Part (e) A 11% Part (f) A 11% Part (g) Enter an expression for Ax in terms of Ax2 and d when the driver just barely avoids collision. Enter an expression for Ax in terms of v, v2, and At. Enter an expression for At in terms of d, v, and v. Calculate the value of At in hours. = A 11% Part (h) V1, Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, A 11% Part (i) Calculate the value of a in meters per second squared. and V2.