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(13%) Problem 8: On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck d = 1.2

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(13%) Problem 8: On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck d = 1.2 mi in front of him. That truck is moving in the same direction at v2 = 44 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval At. The smallest acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. Refer to the figure below. U2 U1 OOO OO 11% Part (a) Enter an expression, in terms of defined quantities, for the distance, Ax2, traveled by the truck during the time interval At. Ax2 = V2 At Correct! * 11% Part (b) Enter an expression for the distance, Ax], traveled by the car in terms of v1, v2 and a. Ax1 = v12 - v2 /(2a) x Attempts Remain Feedback: Given the numerator - v2- You have a sign error in this term. It appears that this numerator involves other terms. Please think about what else should be included in the numerator Your answer is very close and contains something recognizable for all correct terms. Unfortunately there are additional terms in your equation that are not necessary. 11% Part (c) Enter an expression for the acceleration of the car, a, in terms of v1, v2, and At. a = ( V2 - V1 )/At Correct! 11% Part (d) Enter an expression for Ax, in terms of Ax2 and d when the driver just barely avoids collision. Axl = Ax2 + d Correct 11% Part (e) Enter an expression for Ax] in terms of v1, V2, and At. Ax] = ( v1 + v2 ) At/(2) Correct! 11% Part (f) Enter an expression for At in terms of d, v1, and v2. At = ( 2 d/( v1 - V2 ) ) Correct! 11% Part (g) Calculate the value of At in hours. At = 0.1700 Correct * 11% Part (h) Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2. a = - ((V1 - V2)-/2 d) x Attempts Remain Feedback: is available. * 11% Part (i) Calculate the value of a in meters per second squared. Grade Summary a= - 237.811 Deductions Potential 100% sin() cos() tan() IT ( ) 7 8 9 H Submissions cotan() asin() acos() 4 5 6 Attempts remaining: 7 (0% per attempt) atan() acotan() sinh( 1 * 1 2 3 detailed view cosh() tanh() cotanh() + - 0 END 0% 2 0% O Degrees O Radian VO BACKSPACE DEL CLEAR w t 0% Submit Hint Feedback I give up! Hints: 1% deduction per hint. Hints remaining: 2 Feedback: 1 for a 0% deduction No meaningful feedback available for the current submission. Submission History All Date time s are displayed in Pacific Standard Time Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Jan 23, 2023 4:59 PM a = 0.010139 You may have lost the sign. a = 0.01014 Jan 23, 2023 5:03 PM a = 36.478464 a = 36.48 3 Jan 23, 2023 5:16 PM a = - 237.81309 a=-237.8

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