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13) With a previous contractor, the mean time to replace a streetlight was 3.2 days. A city councilwoman thinks that a new contractor is not

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13) With a previous contractor, the mean time to replace a streetlight was 3.2 days. A city councilwoman thinks that a new contractor is not getting the streetlight replaced quickly. Compute the A) 3.211 test statistic for the city councilwoman hypothesis. B) -5.39 C) 0.364 D) 2.60 E) 1.989 14) Using the classical approach, what is (are) the critical values? Use a = 0.05. A) 1.960 B) 2.201 C) 1.796 D) 1.645 E) 1.782 15) What is the proper conclusion of this hypothesis test? A) There is not sufficient evidence to conclude that the mean time to replace a streetlight for the new contractor is more than 3.2 days. B) There is sufficient evidence to conclude that the mean time to replace a streetlight for the new contractor is more than 3.2 days. There is sufficient evidence to conclude that the mean time to replace a streetlight for the new contractor is 3.2 days 16) Find the critical value from a standard normal distribution for a right -tailed test with a = 0.20. A) -2.91 B) 0.5793 C) 2.055 D) 0.84 E) 2.91 F) -2.055 17) Find the critical value from a standard normal distribution for a left -tailed test with a = 0.15. A) 2.965 B) 0.5060 C) -1.035 D) 2.17 E) -2.17 F)-2.965 18) Find the area to the left of -1.24 from a standard normal distribution. A) 0.1151 B) 0.8925 C) 0.1075 D) 0.1093 E) 0.1271 F) 0.9099 19) Find the area to the right of 1.96 from a standard normal distribution. A) 0.0250 B) 0.05 C) 0.10 D) 0.9750 E) 0.90 F) 0.95 20) You wish to test the claim that u > 28 at a level of significance of a = 0.05 and are given sample statistics n = 50, = 28.3, and o = 1.2. Compute the value of the test statistic. Round your answer to two decimal places. A) 2.31 B) 1.77 C) 0.98 D) 3.11 21) Find the critical value from a f distribution with 30 degrees of freedom for a right-tailed test with a = 0.05. A) 0.854 B) 2.750 C) 3.646 D) 0.683 E) 01.697 F) 1.645 22) Find the critical value from a t distribution with 98 degrees of freedom for a left-tailed test with a =0.10. A) -1.290 B) 3.174 C) 2.364 D) -0.845 E) 1.290 F) 0.845

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