1.4 hw no work needed

Use the method of completing the 18 square to write an equation of the circle in standard form * 2 + y 2 - 4x- 184+80=0 the doma 9) complete the Square in x and y to find the center and the radius of the given circle x 2 + y 2 + 2 x - 4 4 - 31 = 0 Center ( x , y ) = ( ) ) radius = 2 x 2 + 2 4 2 + 16 x + 124+ 9zo center ( x y ) = ( ) radius I Find an equation of the circle that Is centered of (X,) ) = ( - 3 - 2) and passes through the point ( x, y ) = (- 3, 4) 12 Find an equation of the circle that Satisfies the given conditions Center ( 4 , - 1), radios y)12 Find an equation of the circle that satisfies the given conditions endpoints of a diameter at ( - 1 , 4 ) and ( 3, 8 ) Find the doma 14 ) Find any intercepts of the graph of the given equation. Do not graph y = - 8 x C xint ( X , ) ) = ( ) yint ( x Y ) = (1 Determine whether the graph of the equation (x ) - 72 + 3x . Possesses symmetry w/ respect to the x axis , yaxis , or orgin ( that apply ) 1 x axis Dorgin I yaxis hone of these 15 - 4 x + 3 y= 8 Xin t ( x,y ) = (I ) yint (x , y ) = ( 1 Is Determine UXaxis ITorgin " yaxis It none of these 16 y 3 - 16 x 2 + 64=0 AxaX 15 Smaller X X int ( x,y ) = ( ] ) - valve Dyaxis yint ( x, y ) = (1] ) - langer x Torgin valve + int (x,y ) = ( ) Phone of these1.4 hw Find the center and the radius y of the circle with the following equation Center (x, 7 ) = L D radius v = units 4 ( X + 3 ) + ( y - 2 ) = 81 Center ( x, 7 ) = ( 1 )) radius X -units Center (x,p - (D) radius = units Find the Center and the radius of the given circle x 2 ty 2 = 8 Center (x,y ) = ( D) Sketch its graph2. [-/6 Points] DETAILS ZILLPRECALC6 1.4.001-006A.XP.TUT.SA. This question has several parts that must be completed sequentially. If you skip a part of the question, you will skipped part. Tutorial Exercise Graph the circle. x 2 + 12 = 16 Step 1 of 2 Identify the center and radius of the given circle using the equation. Recall that the general equation of a circle centered at the origin with radius r is x2 + yz = r. The given equation is x2 + y2 = 16. Compare the given equation with the general equation to identify the center and the radius. The left sides of the equations are the same. Therefore, the center of the given circle is located at what point? ( x, y) = ( ) Setting the right sides of the equations equal to one another gives r = 16. Solve for r. To eliminate the square, take the square root of both sides. 12 = 16 VR = +V r = + Recall that r represents the radius, which must be a positive value. Therefore, what is the radius r of the circle? r = units Submit Skip (you cannot come back). MacBook Air 888 esc F7 F3 F6 F1 X- P/o @ # 2 3 4 5 W E T Y Q R U tab1. [-/1 Points] DETAILS ZILLPRECALC6 1.4.001-006A.XP.TUT. MY NOT Graph the circle. x2 + 12 = 49 Graph Layers After you add an object to the graph you can use Graph Layers to view and edit its properties. Fill . co -10 -9 - 10 Solution Help WebAssign. Graphing Tool 129 Tutorial eBook 2. [-/6 Points] DETAILS ZILLPRECALC6 1.4.001-006A.XP.TUT.SA. MY NOTES ASK YOU MacBook Air esc 388 FO .- @ # o 1 2o 1 2 W 5 8 Q W E T tab R O A S D caps lock F G H J K Z shift X C V B N M 96 control option command7. [-/3 Points] DETAILS ZILLPRECALC6 1.4.006. Find the center and the radius of the given circle. ( x+ 5) 2 + (y - 3 ) 2 = 16 center (x, y ) = radius Sketch its graph. Graph Layers After you add an object to the gr can use Graph Layers to view ar properties. Fill V . -10 -9 -8 -7 - 5 6 7 8 10 No Solution Help WebAssign. Graphing Tool eBook MacBook Air esc F1 F3 F7 @ # 2 3 6 tab Q W E R T Y U A S caps lock D F G H