#14

When asked whether marriage is becoming obsolete, 783 out of 2010 randomly selected adults who responded to a poll said yes. 1-PropZInt Refer to the output given. Assuming the conditions for the CLT (.36823,.41087) were met, complete parts (a) and (b) below. p =.3895522388 n = 2010 . . . a. Report a 95% confidence interval for the proportion. Use correct wording. (Round to three decimal places as needed.) O A. There is a 95% chance that the population proportion of people who think marriage is obsolete is between and O B. With 95% confidence, the population proportion of people who think marriage is becoming obsolete is between and b. Is it plausible to claim that a majority think marriage is becoming obsolete? O A. Yes, it is a plausible claim because the confidence interval does not contain 50%. O B. Yes, it is a plausible claim because the confidence interval contains values above 50%. O C. No, it is not a plausible claim because the confidence interval does not contain values above 50%. O D. No, it is not a plausible claim because the confidence interval contains 50%.In a simple random sample of 1200 people age 20 and over in a certain country, the proportion with a certain disease was found to be 0.135 (or 13.5%). Complete parts (a) through (d) below. E> a. What is the standard error of the estimate of the proportion of all people in the country age 20 and over with the disease? SEest : |:| (Round to four decimal places as needed.) b. Find the margin of error, using a 95% condence level, for estimating this proportion. m=D (Round to three decimal places as needed.) c. Report the 95% condence interval for the proportion of all people in the country age 20 and over with the disease. The 95% condence interval for the proportion is (D,|:D . (Round to three decimal places as needed.) d. According to a government agency, nationally, 12.5% of all people in the country age 20 or over have the disease. Does the condence interval you found in part (c) support or refute this claim? Explain. The confidence interval |:l this claim, since the value E El contained within the interval for the proportion. (Type an integer or a decimal. Do not round.) According to a 2017 report, 37% of adults aged 18 to 29 had student loan debt. Suppose in a random sample of adults from this age group 74 out of 180 had student loan debt. Complete parts (a) and (b) below. K Click the icon to view a graphical technology output for this situation. a, Give he null and alternative hypotheses to test that the student loan rate is not 37%. TeChnOIOQy OUtpUt H0: p Y Ha: p Y (Type integers or decimals. Do not round.) b. Report the test statistic (z) from the output given. z=D (Type an integer or a decimal rounded to four decimal places as needed.) 1-PropZTest = 1.1424