140 A fission reaction is given by 236U92 140Xe54+ 94Sr38 + x + y, where x and y are two particles. Considering 236U92 to be at rest, the kinetic energies of the products are denoted by Kxe, Ksr, K.(2MeV) and K, (2MeV), 236 140 92 respectively. Let the binding energies per nucleon of 235U, Xe and Sr be 7.5 MeV, 8.5 MeV and 8.5 MeV respectively. Considering different conservation laws, the correct option(s) is(are) (A) x n, y=n, Ksr 129MeV, Kxe-86 MeV (B) x p, y=e, Ksr 129 MeV, Kxe = 86 MeV (C) x p, y=n, Ksr 129 MeV, Kxe = 86 MeV (D) x=n, y=n, Ksr=86 MeV, Kxe = 129 MeV