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14.4. You can chick on the Rewiow ink to aocess the sectiontin your e Text. Caculate the rale of the reaction whon (N1O5)=5.5102M. The following

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14.4. You can chick on the Rewiow ink to aocess the sectiontin your e Text. Caculate the rale of the reaction whon (N1O5)=5.5102M. The following reaction is first ordes in N2O5 t Express your answer using dwo significant tigures. N2O8(g)NO3(g)+NO2(g) The rate constant for the reaction at a certain tomperature is 0.053/s. Correct The rate law for areaction A products is piven by rate=k(A)n where k is a constant of propordenaly caled the rate constant ane n is the reaction order. The raacton a fiat ordor in N2O3, so rate=[N2O5] Inserting the values of the tate constart and concentration of N2O5 pives the reve as rate=(0.053/3)(5.5102M) The following reactuen is firbf order in N3O5. What vould the rale of the rest thon be at the garee concentraion as in Part A f the reacton wiens aecund ordart (Asuans N2O5(x)/NO3(g)+NO2(g) the same numievicar valub tor tie tale constart with the aperopriate unts.) Express your anwwer uting tho signincant ageres. The rate constant for the reaction at a certain temperature is 0.053/3. x. Incorrect: Try Again; 6 attempts remaining The following reaction is first order in N2O5 : X ineorrect; Try Again; 6 attempts remaining N2Og(g)NO3(g)+NO2(g) The rate constant for the coaction at a cortain temperature is 0.053/5 Part c What would the rate of the reaction be at ine same concertratoce as in Part A it the reacbon were ampo order? Express your answer using two signiticant fgures

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