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When two births are randomly selected, the sample space for genders is bb, bg, gb, and 99. Assume that those four outcomes are equally likely. Construct a table that describes the sampling distribution of the sample proportion of girls from two births. Does the mean of the sample proportions equal the proportion of girls in two births? Does the result suggest that a sample proportion is 1 1 an unbiased estimator of a population proportion? For the entire population, assume the probability of having a boy is E, the probability of having a girl is E, and this is not affected by how many boys or girls have previously been born. Determine the probabilities of each sample proportion. Sample proportion of girls Probability I (Type integers or simplied fractions.) Does the mean of the sample proportions equal the proportion of girls in two births? . '3 A. No, the mean of the sample proportions and the population proportion are not equal. 1 [:3 B. Yes, both the mean of the sample proportions and the population proportion are E. 1 [j 0. Yes, both the mean of the sample proportions and the population proportion are E' 1 C '3 D. Yes, both the mean of the sample proportions and the population proportion are I. Does the result suggest that a sample proportion is an unbiased estimator of a population proportion? A. Yes, because the sample proportions and the population proportion are not the same. B. No, because the sample proportions and the population proportion are not the same. The table to the right shows the results from a test for a disease among a group of patients. Find the probability of selecting a subject with a positive test result, given that the subject does not have the disease. Why is this case problematic for test subjects? Positive Negative Disease 358 9 No Disease 6 1127 D The probability is . (Round to ve decimal places as needed.) Why is this case problematic for test subjects? Choose the correct answer below. . If a patient tests positive for a disease without having the disease, the patient might be forced to change doctors. . If a patient tests positive for a disease without having the disease, the patient is likely to receive the best health care options available. . If a patient tests positive for a disease without having the disease, the patient is unlikely to serve as a test subject for future studies. . If a patient tests positive for a disease without having the disease, the patient might be subjected to stress, medication, and further testing that are unnecessary. Find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1. z: -0.94 2:121 ,09 The area of the shaded region is . (Round to four decimal places as needed.) Refer to the technology output given to the right that results from measured hemoglobin levels (g/dL) in 100 randomly selected adult females. The results to the right are based Tlnterval on a 95% confidence level. Write a statement that correctly interprets the condence level. (13.080.13.568) 2 = 13.324 Sx = 1 .232 n = 100 Choose the correct answer below. We have 95% condence that the limits of 13.080 g/dL and 13.568 g/dL contain the true value of the mean hemoglobin level of the population of all adult females. Approximately 95% of the hemoglobin levels in the population of all adult females is between 13.080 g/dL and 13.568 g/dL. There is a 95% probability that the limits of 13.080 g/dL and 13.568 g/dL contain the true value of the mean hemoglobin level of the population of all adult females. .6666} The true value of the mean hemoglobin level of the population of all adult females is between 13.080 g/dL and 13.568 g/dL. Use technology to nd the Pvalue for the hypothesis test described below. The claim is that for the population of adult males, the mean platelet count is u