#15,16 & N.R # 8

Numerical Response Given cos 0 = 0.342 0 and 90

Given 0.342 0 and 900 < O < , determine the value of o, to the nearest Numerical Response degree. 0(csc0 sec0) = cot0 < 0 27t is 15. The smallest non-permissible value for cos 2 C. D. 16. Angle O is decreased by X. The tangent of the new angle is A. tan O + 1 B. tan 0 1 tan 0 + 1 1 tan 0 tan 0 1 D. 1 + tan O