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(1,6) (0,5) Assuming that f(x) is of the form A . BY, write an expression for f (I): f(x) =Rewrite the following logarithms in expanded

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(1,6) (0,5) Assuming that f(x) is of the form A . BY, write an expression for f (I): f(x) =Rewrite the following logarithms in expanded form by applying the properties of logarithms. a. log b. logCondense the following expressions into a single logarithm by applying the properties of logarithms. . You are only allowed to use integer exponents. . Use sqit(...) to deal with fractional exponents. . Make sure your final answer is written as a single logarithm. H a. 3 log(x) + 7log(2) - 2 log(y) = b. log(x) - 7log(y) - 3 log(=) = C. -log(@) - - to | 09 log(y) to | -J log(z) =Exponential Growth and Decay Exponential growth and decay problems follow the model given by the equation A(t) = Pert. . The model is a function of time t . A(t) is the amount we have after time t P is the initial amount, because for t = 0, notice how A(0) = Pelt = Pe = P is the growth or decay rate. It is positive for growth and negative for decay Growth and decay problems can deal with money (interest compounded continuously), bacteria growth, radioactive decay, population growth etc. So A(t) can represent any of these depending on the problem. Practice The growth of a certain bacteria population can be modeled by the function A(t) = 850e0.06it where A(t) is the number of bacteria and t represents the time in minutes. a. What is the initial number of bacteria? (round to the nearest whole number of bacteria.) b. What is the number of bacteria after 20 minutes? (round to the nearest whole number of bacteria.) C. How long will it take for the number of bacteria to double? (your answer must be accurate to at least 3 decimal places.)Suppose $10000 is invested at 5% interest compounded continuously. How long will it take for the investment to grow to $20000? Use the model A(t) = Pe" and round your answer to the nearest hundredth of a year. It will take years for the investment to reach $20000.Research shows that the radioactive isotope Iron-55 has a half-life of 2.737 years Use the following to construct a function that will model the amount of Iron-55 remaining after t years, from an initial amount of 20 kg. Q (t) = Pert Where Q (t) describes the amount of Iron-55 remaining after t years from an initial quantity of P kg. 1. Q (t) = 2. How long (in years) will it take for the amount of Iron-55 remaining to reach 3 kg? Round to three decimal places.Using a change of base formula, one can write logs(20) logo(7) = logm(P), where m= P =

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