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16%% of all Americans live in poverty. If 43 Americans are randomly selected, find the probability that a. Exactly 8 of them live in poverty.

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16%% of all Americans live in poverty. If 43 Americans are randomly selected, find the probability that a. Exactly 8 of them live in poverty. b. At most 10 of them live in poverty. 8 c. At least 7 of them live in poverty. d. Between 2 and 7 (including 2 and 7) of them live in poverty. Hint: Hint Video on Finding Binomial Probabilities ' [+] Question Help: Message instructor Submit

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