Answered step by step
Verified Expert Solution
Question
1 Approved Answer
17 + X V fx A B C D E F G H J K L M Mass Added to Cylinder Time of fall, T
17 + X V fx A B C D E F G H J K L M Mass Added to Cylinder Time of fall, T (seconds) Average T Value Units Number m1 (kg) m2 (kg) EM (kg) 1/EM (kg^-1) R1 R2 R3 (seconds) a = 2D/T^2 (m/s^2) Mass of the right cylinder, C 25 g 0.05 0.00 50.35 0.019860973 0.093 0.0773 0.0452 Mass of the left cylinder, C2 25.3 g 0.10 0.05 50.45 0.019821606 1521 1049 1153 Distance of fall, D 60 cm UTAWNY 0.15 0.10 50.55 0.019782394 1349 1311 1194 Least count of the timer 0 0.20 0.15 50.65 0.019743337 1353 1312 1668 Least count of the balance 0 0.25 0.20 50.75 0.019704433 1398 1464 1965 0 AM = m1 + C1 - m2 - C2 EM = m1 + C1 + m2 + C2 Plot a graph between 1/EM and a. Determine the slope from a linear curve fit and calculate the value of g by applying Equation (3). Slope of graph 'g' calculated from slope 6 Standard value of 'g' (m/s^2) 9.8 Percent error in the experimental value of g = 8 Standard error in slope of graph 9 Probable percent error in slope of graph 0 Probable error in difference of mass Probable percent error in difference of mass Probable percent error in 'g' calculated from slope
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started