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18. How many grams of sodium carbonate are required to neutralize 750 cm3 of 5.0 M HCl? Na2CO3 + 2HCl 2NaCl + H2O +

18. How many grams of sodium carbonate are required to neutralize 750 cm3 of 5.0 M HCl? 

Na2CO3 + 2HCl  2NaCl + H2O + CO2

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