1.A true Six Sigma process aims for a centered process with C_pk= 1.5. That is, while keeping the process mean at the center (of the specification limits), it also puts the specification limits in 4.5 standard deviations away on both sides.

(Hint: Although this problem does not give you specific value for important process parameters, such as process mean, standard deviation, specification limits, you can still solve it by relying on the information provided above. For example, you can substitute with your own values for those parameters.)

1)Calculate the DPMO in this case. (Note: round the answer to the next integer.)

2)Please re-calculate the DPMO when the process mean is shifted to the right by 1.5 standard deviation. (Note: round the answer to the next integer.)

3)Now, let's compare the process with a centered process with C_pk= 1.00. What is the DPMO for this new process?

4)When a system operates on C_pk= 1.5, even the mean shifts within 1.5 standard deviation, it still generates less defects than a system with C_pk= 1.0. Please discuss what are two important factors that allow you to have such a big C_pk. (Hint: think about the equation for C_pk).