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1.Compute a 90% confidence interval for the mean age of the students. statement to interpret the interval. b)Find a 90% confidence interval for the standard

1.Compute a 90% confidence interval for the mean age of the students. statement to interpret the interval.

b)Find a 90% confidence interval for the standard deviation of the ages.Interpret.

2.Find a 95% confidence interval for the mean difference in height between males and females.

Height:Males:Females:

What conclusion can you draw

3.Find a 90% confidence interval for the proportion of smokers.

statement to interpret the interval.

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