1.)Construct the confidence interval for the population mean . c=0.98, x=4.6, =0.4, and n=48 A 98% confidence interval for is ,. (Round to two decimal places as needed.) 2.)Find the minimum sample size n needed to estimate for the given values of c, , and E. c=0.95, =7.1, and E=1 Assume that a preliminary sample has at least 30 members. n=enter your response here (Round up to the nearest whole number.) 3.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean price of $131.00. Assume the population standard deviation is $17.50. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (enter your response here,enter your response here). (Round to two decimal places as needed.) 4.)Construct the confidence interval for the population mean . c=0.98, x=7.2, =0.6, and n=50 A 98% confidence interval for is ,. (Round to two decimal places as needed.) 5.)Construct the confidence interval for the population mean . c=0.90, x=7.3, =0.5, and n=50 A 90% confidence interval for is ,. (Round to two decimal places as needed.) 6.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $124.00. Assume the population standard deviation is $17.70. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (enter your response here,enter your response here). (Round to two decimal places as needed.) 7.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 35 business days, the mean closing price of a certain stock was $115.45. Assume the population standard deviation is $10.97. The 90% confidence interval is (enter your response here,enter your response here). (Round to two decimal places as needed.) 8.)A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes is 1.9 minutes and that the population of times is normally distributed. 9 8 7 7 7 7 6 10 6 12 10 9 8 8 10 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (enter your response here,enter your response here). (Round to one decimal place as needed.)

9.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals.

A random sample of 55 55 home theater systems has a mean price of $ 141.00 141.00. Assume the population standard deviation is $ 15.70 15.70.

Construct a 90% confidence interval for the population mean.

The 90% confidence interval is (

enter your response here ,

enter your response here ). (Round to two decimal places as needed.)

10.)Find the critical value zc necessary to form a confidence interval at the level of confidence shown below. c=0.96 zc=enter your response here (Round to two decimal places as needed.)

11.)Find the minimum sample size n needed to estimate for the given values of c, , and E. c=0.95, =5.4, and E=1 Assume that a preliminary sample has at least 30 members. n=enter your response here (Round up to the nearest whole number.) 12.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 63 dates, the mean record high daily temperature in a certain city has a mean of 83.82F. Assume the population standard deviation is 15.04F. The 90% confidence interval is ________enter your response here,enter your response here). (Round to two decimal places as needed.) The 95% confidence interval is______(enter your response here,enter your response here). (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below.

The 95% confidence interval

The 90% confidence interval Interpret the results. A. You can be 90% confident that the population mean record high temperature is outside the bounds of the 90% confidence interval, and 95% confident for the 95% interval. B. You can be 90% confident that the population mean record high temperature is between the bounds of the 90% confidence interval, and 95% confident for the 95% interval. C. You can be certain that the population mean record high temperature is either between the lower bounds of the 90% and 95% confidence intervals or the upper bounds of the 90% and 95% confidence intervals. D. You can be certain that the mean record high temperature was within the 90% confidence interval for approximately 57 of the 63 days, and was within the 95% confidence interval for approximately 60 of the 63 days.

13.)Find the margin of error for the given values of c, , and n. c=0.95, =3.9, n=36 LOADING... Click the icon to view a table of common critical values.Level of Confidence zc 90% 1.645 95% 1.96 99% 2.575

E=_____enter your response here (Round to three decimal places as needed.)

14.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 39 business days, the mean closing price of a certain stock was $108.68. Assume the population standard deviation is $9.93.

The 90% confidence interval is____(enter your response here). (Round to two decimal places as needed.) The 95% confidence interval is______ (enter your response here). (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below.

The 90% confidence interval

The 95% confidence interval

Interpret the results.

A. You can be 90% confident that the population mean price of the stock is outside the bounds of the 90% confidence interval, and 95% confident for the 95% interval.

B. You can be certain that the population mean price of the stock is either between the lower bounds of the 90% and 95% confidence intervals or the upper bounds of the 90% and 95% confidence intervals.

C. You can be 90% confident that the population mean price of the stock is between the bounds of the 90% confidence interval, and 95% confident for the 95% interval.

D. You can be certain that the closing price of the stock was within the 90% confidence interval for approximately 35 of the 39 days, and was within the 95% confidence interval for approximately 37 of the 39 days.

15.)You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 61 dates, the mean record high daily temperature in a certain city has a mean of 83.20F. Assume the population standard deviation is 15.11F. The 90% confidence interval is ___(enter your response here,enter your response here). (Round to two decimal places as needed.) The 95% confidence interval is__ (enter your response here,enter your response here). (Round to two decimal places as needed.) Which interval is wider? Choose the correct answer below.

The 90% confidence interval

The 95% confidence interval Interpret the results. A. You can be 90% confident that the population mean record high temperature is between the bounds of the 90% confidence interval, and 95% confident for the 95% interval. B. You can be certain that the population mean record high temperature is either between the lower bounds of the 90% and 95% confidence intervals or the upper bounds of the 90% and 95% confidence intervals. C. You can be 90% confident that the population mean record high temperature is outside the bounds of the 90% confidence interval, and 95% confident for the 95% interval. D. You can be certain that the mean record high temperature was within the 90% confidence interval for approximately 55 of the 61 days, and was within the 95% confidence interval for approximately 58 of the 61 days.

16.)Find the critical value zc necessary to form a confidence interval at the level of confidence shown below. c=0.93 zc=____enter your response here (Round to two decimal places as needed.)

17.)Find the minimum sample size n needed to estimate for the given values of c, , and E. c=0.90, =9.8, and E=2 Assume that a preliminary sample has at least 30 members. n=enter your response here (Round up to the nearest whole number.) n=____enter your response here (Round up to the nearest whole number.)

18.)Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence interval of (2.7,4.3) when estimating the mean height (in centimeters) of a sample of seedlings. The estimated margin of error is_____enter your response here. The sample mean is_____enter your response here.

19.)Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H0 for the given level of significance . Right-tailed test with test statistic z=1.58 and =0.07 P-value=_____enter your response here (Round to four decimal places as needed.)

20.)A nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.09 pounds. At =0.06, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. A. H0: >3.4 Ha: 3.4 B. H0: =3.4 Ha: 3.4 Your answer is correct.C. H0: 3.3 Ha: >3.3 D. H0: >3.3 Ha: 3.3 E. H0: 3.3 Ha: =3.3 F. H0: 3.4 Ha: >3.4 (b) Identify the standardized test statistic. z=negative .82 (Round to two decimal places as needed.) (c) Find the P-value._____ (Round to three decimal places as needed.)

21.)A company claims that the mean monthly residential electricity consumption in a certain region is more than 890 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 65 residential customers has a mean monthly consumption of 930 kWh. Assume the population standard deviation is 124 kWh. At =0.10, can you support the claim? Complete parts (a) through (e). (a) Identify H0 and Ha. Choose the correct answer below. A. H0: =890 (claim) Ha: 890 B. H0: 930 Ha: >930 (claim) C. H0: 890 Ha: >890 (claim) Your answer is correct.D. H0: >930 (claim) Ha: 930 E. H0: >890 (claim) Ha: 890 F. H0: =930 Ha: 930 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical values are _____enter your response here. B. The critical value is______ enter your response here.