1/do + 1/di = 1/t Ent Physlet Physics by Christian and Belloni: Problem 33.7 (compadre.org) Open the simulation. Image in Plane, Concave, and Convex mirrors. Click on plane mirror below the simulation. Problem 33.7: Objects in mirror are closer than they appear. You will see the figure to the left, and moving the cursor gives you the yellow box with x and y coordinates in meters. 1. a. Verify that you can get (1.5, 0) at the base of the image and (2.5, 0) at the mirror's base (on the optical axis). Yes/No. Object distance do = _m. Image distance dj = -_m. b. Does do = -di? Yes/No. Side mirrors on cars have a label that says "objects in mirror are closer than they appear." Example 23-6 in the lecture works this. We will simulate a concave and then a convex mirror, to see which one it is and why this is so. 2. a. Click on concave mirror. This is similar to the figure in the lecture, shown to the left. The rays from the object's head reflect down and to the left, and their focus goes completely off the page. Its image distance is Closer/Further, from the mirror than the object. The image is Erect/Inverted. b. Click on convex mirror. This is similar to the figure in the lecture, shown to the left. However the simulation's figure shows rays from the object (not the eye). This image distance is Closer/Further, from the mirror than the object. The image is Erect/Inverted.| 3. Which of the two types of mirror has the image further from the mirror than the object? Concave/Convex. Physlet Physics by Christian and Belloni: Exploration 33 .4 (compadre.org) Open the simulation. Focal Point and Image Point, Concave and Convex Mirrors. Click on Concave mirror and Parallel Beam below the simulation. The parallel source is the green circle, with 3 rays going horizontally below the optical axis, and being reflected by the concave mirror "up and to the left". Where they converge on the optical axis is the focal point for the concave mirror. 4. a. Use the cursor to measure the distance from the focal point to the mirror. f=_ m. This focal distance is + because it's to the left of the mirror. Calculate the power, P = 1/f = Move the source upwards to the optical axis, by clicking on it and pulling it upwards. The 3 rays will move