1-In engineering and physics we talk of "g-forces". Where 1 G = 9.8 m/s^2 (the acceleration due to gravity). Sometimes they are referred to in what I call "science slang" as "G-forces" or just "G's". G's actually is physically correct because we know there is no force unless you multiply by the mass. The quarterback in Q3 experienced how many "G's"?

Bob Beamon's long jump at the 1968 Olympics was literally "like nothing seen before." As you will see in the upcoming video he broke the world record by 57 cm (we will probably be converting that to inches in the Exercise). He would have won the 2012 Olympics long jump by a 55 cm!

Bob Beamon's historic leap.

2-In this quiz we are going to "re-engineer" Bob Beamon's historic long jump in the 1968 Olympics. We know he jumped 8.90 m. Just for our American sensibilities let's convert that to feet.

3-How many inches is 0.2 feet?

4-Now let's go back to the 8.9 meters for the "range" of the jump. Actually, that was where his feet hit and then due to his extraordinary athletic skill and training, he was able to contort his body over his feet to achieve that distance. However, we are going to calculate how far his center of mass traveled.According to an article in "Wired" magazine that analyzed this jump, Beamon took off with an initial velocity of 10.1 m/s at an angle of 26.5 degrees (so much for that optimum of 34 degrees!). What was Beamon's speed in the x-direction?

Much of the raw data we are using in this analysis comes from an article written by Rhett Allain for "Wired" magazine in 2012. Here is a link to the full article. https://www.wired.com/2012/08/long-jump-air-density/

5-What was Beamon's initial speed in the y-direction?

6-Using Beamon's two velocites in the y-direction (up and down), calculate the time he was in the air.

7-Now that we know the time in the air AND the speed in the x-direction. Calculate the range his center of mass traveled.

8-Calculate your answer in Q6 to feet.