1.Poisson = 3.5. Poisson

a) P(0)

b) P(2)

c) P(1)

2.Distribution of Poisson

a)= 0.8, si x= 2

b)= 12.0, si x= 8

c)= 2.5, si x= 3

3.The number x of people admitted to an intensive care unit in a particular hospital, on any given day, has a Poisson probability distribution with an average equal to four (4) people per day. What is the probability that the number of people admitted to an intensive care unit on a particular day will be two (2)? Solve using Poisson's formula.

4.Calculate with a) the formula and b) the table, the Poisson probability when = 4, if x = 4. Certify that with both methods you get the same result