1 The modelY 0 1 X 2 X 2 cannot be estimated by Excel because of the nonlinear term True False 2 Ifn 25 and 05 in a right tailed test of a mean with unknown, thecriticalvalueis 0179 1 645 1 711 1 960 3 The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm The process standard deviation is known to be 0 77 gm A random sample of 49 candy bars yields a mean weight of 55 82 gm Which are the hypotheses to test whether the mean is smaller than it is supposed to be H 0 56,H 1 56H 0 56,H 1 56H 0 56,H 1 56H 0 56,H 1 56 4 To estimate the average annual expenses of students on books and class materials a sample of size 36 is taken The sample mean is $850 and the sample standard deviation is $54 A 99 percent confidence interval for the population mean is $826 82 to $873 18 $825 48 to $874 52 $832 36 to $867 64 $823 72 to $876 28 5 IfSSEis near zero in a regression, the statistician will conclude that the proposed model probably has too poor a fit to be useful True False

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1.The modelY= 0 + 1 X+ 2 X 2 cannot be estimated by Excel because of the nonlinear term. True False 2.Ifn= 25 and= .05

1.The modelY=₀+₁X+₂X²cannot be estimated by Excel because of the nonlinear term. True False

2.Ifn= 25 and= .05 in a right-tailed test of a mean with unknown, thecriticalvalueis: .0179 1.645 1.711 1.960

3.The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm. The process standard deviation is known to be 0.77 gm. A random sample of 49 candy bars yields a mean weight of 55.82 gm. Which are the hypotheses to test whether the mean is smaller than it is supposed to be?

H₀:< 56,H₁: 56H₀: 56,H₁:< 56H₀:= 56,H₁: 56H₀: 56,H₁:> 56

4.To estimate the average annual expenses of students on books and class materials a sample of size 36 is taken. The sample mean is $850 and the sample standard deviation is $54. A 99 percent confidence interval for the population mean is: $826.82 to $873.18

$825.48 to $874.52

$832.36 to $867.64

$823.72 to $876.28

5.IfSSEis near zero in a regression, the statistician will conclude that the proposed model probably has too poor a fit to be useful. True False