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1.The results of a common standardized test used in psychology research is designed so that the population mean is 170 and the standard deviation is

1.The results of a common standardized test used in psychology research is designed so that the population mean is 170 and the standard deviation is 50. A subject earns a score of 265. What is the z-score for this raw score? z-score =

2.Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 73.8 inches tall. (to 2 decimal places)=

3.On a recent quiz, the class mean was 76 with a standard deviation of 3.9. Calculate the z-score (to 2 decimal places) for a person who received score of 86. z-score=

4.The scores on a standardized test are normally distributed with a mean of 80 and standard deviation of 15. What test score is 1.1 standard deviations below the mean? 5.What is the probability of a z-score less than +2.02? Round your answer to the nearest hundredth of a percent.

6.What is the probability of a z-score greater than +2.02? Round your answer to the nearest hundredth of a percent.

7.What is the probability of a z-score less than -1.97? Round your answer to the nearest hundredth of a percent.

8.What is the probability of a z-score greater than -1.97? Round your answer to the nearest hundredth of a percent.

9.What is P(Z > ?2.71)? Round your answer to the nearest hundredth of a percent.

10.The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $2000 and the standard deviation is $115.

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1655 1770 1885 2000 2115 2230 2345 Distribution of Prices QWeights for a certain species of newt are normally distributed with a mean of 43 grams and standard deviation 7 grams. The bell curve below represents the probability distribution for newt weights. The scale on the horizontal axis is equal to the standard deviation. Fill in the three indicated boxes for the mean and 2 standard deviations from the mean in both directions. X 19.7 25.3 22.7 29.4 10 34.4 33.9 36.1 29.2\fM = 51 0 = 5 H- 30 4-20 H- O Hto u+20 4+ 30

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