$[20]27C$ of air flows into the tube with a diameter of $10cm$ and a length of $1m$ at normal pressure. The

bulk$-$stream velocity in the tube is $2\frac{m}{s},$ and the heat flux from the surface of the tube varies depending on

the position in the $x$ direction as follows.

$\frac{q_r}{A}=q_0[1-cos(\frac{4x}{L})]$

In the above equation, q$0=0\mathrm{.}541k\frac{W}{m^2},$ and $L$ is the length of the tube. At $27C,$ the density of air $(p)$ is $1\mathrm{.}18k\frac{g}{m}3,$

the specific heat $($cp$)$ is $1\mathrm{.}01k.\frac{J}{k}gC,$ and the thermal conductivity $(k)$ is $0\mathrm{.}0262\frac{W}{m}*C.$ In this case, calculate the

temperature of the air leaving the tube.