2 (1 point) In this problem you will calculate f 4:173 d1: by using the formal definition of the definite integral: 0 b n d = 1' * A . fa f(:E) :2 \"13010 L: rank) as] (a) The interval [0, 2] is divided into n equal subintervals of length A512. What is Am (in terms of n)? A3: = (b) The right-hand endpoint of the kth subinterval is denoted (17:. What is :13]: (in terms of k and n)? * 112k: (0) Using these choices for 33,: and Am, the definition tells us that 2 1). [0 4:33 d2? : \"113010 [E f(m;;)A:c] . What is f(:1:,";)A:v (in terms of k and n)? f($i)A~T = n (d) Express 2 f(a:;';)A$ in closed form. (Your answer will be in terms of n.) k:1 i mamas = k:1 (e) Finally, complete the problem by taking the limit as n > 00 of the expression that you found in the previous part. 2 n [0 4:133 dm : \"13130 [2 fawn] =