2. [10 pts] We are told that 67% of the Missoula population has been skiing. We are going to take a random sample of 120 students. a. What does our random variable P represent in this instance? The random variable P represents the sample proportion of students who have skiing from the random sample of 120 students from the Missoula population. gone b. What does the distribution of P look like? Justify your response (Hint: reference the CLT) then draw the distribution with the mean and standard deviation clearly labeled. (Show work for and p). Hp-30 0.67-(3-0.0429) = 0.5413 0.67(1-0.67) = 120 = Hp-20=0.67-(2.0.0429)=0.5842 0.67(1-0.33) Hp-p=0.67-(0.0429) = 0.6271 = 120 Hp = 0.67 0.2211 = 120 H+0=0.67+(0.0429) = 0.7129 I mean =0.0018125 H+20=0.67+(2.0.0429) = 0.7558 0.5413 0.5842 0.6271 0.67 0.7129 0.755% 0.