2. (2.5 points) Let f (x) = vx over the interval [1, 4]. Calculate the exact value of the surface area of the surface generated by revolving the graph of f (x) around the x- axis. (The surface area formulas: Surface Area = (2nf(x) 1+ (f'(x)) )dx & Surface Area = Ja(2ng() 1+ (g'(v)) )dy) 2)