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2. (5 pts) The reaction CHCl3(g)+Cl2(g)CCl4(g)+HCl(g) has the following rate law: Rate = k[CHCl3][Cl2]. If the concentration of CHCl3 is increased by a factor of

2. (5 pts) The reaction CHCl3(g)+Cl2(g)CCl4(g)+HCl(g) has the following rate law: Rate = k[CHCl3][Cl2]. If the concentration of CHCl3 is increased by a factor of five while the concentration of Cl2 is kept the same, what happens to the rate

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