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2) [5pts] Compute N! ( ( 25 ) 4) = ZK=0 K! ( N-K)! (2k - N)4 2N (4) exactly as a function of N,
2) [5pts] Compute N! ( ( 25 ) 4) = ZK=0 K! ( N-K)! (2k - N)4 2N (4) exactly as a function of N, and compare to the expectation based on Gaussian limit of the binomial coefficient for large N
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