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2. According to a recent Newspaper article, the population mean average amount of time people in California spend eating and drinking per day is 1.25

2. According to a recent Newspaper article, the population mean average amount of time people in California spend eating and drinking per day is 1.25 hours. Test the claim that the population mean average number of hours spent eating and drinking really is 1.25 hours.

a) Write the null and alternative hypothesis.

b) Label whether the null or the alternative is the claim.

c) Tell whether this is a left tail test, a right tail test, or a two tail test.

2. What are the assumptions we should check if we want to use sample data to calculate a two-population mean confidence interval?

10. A two-population mean confidence interval is (6.233C , 4.718C). They used a 90% confidence level.

a) Is the mean from population 1 significantly higher, significantly lower, or not significantly different from the mean from population 2? Explain how you know.

b) How much lower could the population mean from population 1 than the population mean from population 2?

c) Write the two-population confidence interval sentence explaining this confidence interval.

18. An experiment was done to test the effectiveness of medicine that lowers cholesterol. An experiment was conducted and adults were randomly assigned into two groups. The groups had similar gender, ages, exercise patterns and diet. Of the 410 adults in the treatment group, 49 of them showed a decrease in cholesterol. Of the 420 adults in the placebo group, 38 of them showed a decrease in cholesterol. Was the medicine effective in lowering cholesterol? Use the following 99% confidence interval from Statcato to determine if the percentage of people on the medicine that have a decrease in cholesterol (population 1) is higher than the percentage from the placebo group (population 2).

Number of Events :

Sample 1 : 49

Sample 2 : 410

Number of trials :

Sample 1: 410

Sample 2 : 420

Proportion:

Sample 1: 0.120

Sample 2: 0.090

Sample proportion difference = 0.029

Margin of error = 0.055

99.0% =(-0.0258, 0.0838)

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