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2 and 3 please (2) Find an inverse of 23 modulo 120. Subsequently, Solve the congruent equation 23x = 3 (mod 120) for X. (Hint:

2 and 3 please
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(2) Find an inverse of "23" modulo "120". Subsequently, Solve the congruent equation 23x = 3 (mod 120) for "X". (Hint: Use Euclid's Algorithm & Extended Euclid's Algorithm) Definition: an integer such that aa = 1 (mod m) is said to be an inverse of a modulo m. (3) Use the Fermat's little theorem to find: 39 (mod 11) Theorem: ab-1 : 1 (mod p)

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