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2. Assume the node is in the usual info-link form with the info of type int. (list and ptr are pointers of type nodeType) list

2. Assume the node is in the usual info-link form with the info of type int. (list and ptr are pointers of type nodeType) list = new nodeType; list->info = 10; ptr = new nodeType; ptr->info - 13; ptr->link - NULL; list->link - ptr; ptr - new nodeType; ptr->info - 18; ptr->link = list->link; list->link = ptr; cout info info link; cout info

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