2 = e4r +2r-2 42+2r-2 Part 3 of 3 From the previous step we have ex (4r2 + 2r-2) = 0. Since ex is never 0, then we know 42 + 2r 2 = 0. Solving the above equation gives the solutions to the quadratic equation. r = = (smaller value) (larger value)