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2. For three events A, B, C, we have A (B C) = (A B) (A C). (1.1) and A (B C) = (A B)
2. For three events A, B, C, we have A (B C) = (A B) (A C). (1.1) and A (B C) = (A B) (A C). (1.2) Using the above equations (1.1) and (1.2), prove the following: (a) A = (A B) (A Bc). (b) (A B) and (A Bc) are disjoint, that is (A B) (A Bc) = (c) P (A) = P (A B) + P (A Bc).
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Bayesian Data Analysis
Authors: Andrew Gelman, John B Carlin, Hal S Stern, David B Dunson, Aki Vehtari, Donald B Rubin
3rd Edition
