2. How long must a bay be to act as a quarter wavelength resonator, resonant with a 12 hour 25 minute tide, if the bay is 60 meters deep (H)? (10 points) The relevant equations to use: Celerity: c = A/T = (g H) /2, so L=A/4, so T=4L (g H"Y/; solve for the length L. 10 pts. I A r H = Depth deep ocean of Bay B ay of Fundy length 2. How deep is the Bay of Fundy, if it is 200 kilometers long and acts as a quarter wavelength resonator, resonant with a 12 hour 25 minute tide? PowerPoint 11a. The relevant equations are celerity c = A/T = (g H) V/2, L=A/4, so T=4L (g H''/?; solve for H, depth. L deep ocean =gt i Substitute the numbers into the equation: 44700 = 4 * (200000) * (9.8 * H)Y/2 447/8000 = (9.8 * H)2/2 447 1 8000 \\98+H 447 V9.8 = H = 8000 VH ~ 5.717 H ~ 32.684m