$2$kg of barium chloride, BaCl$2,$ is dissolved in sufficient water to form a saturated solution at $100\backslash$deg C$.$ The solution is then cooled to $20\backslash$deg C to $.$ Assuming that $5\%$ of the original water is lost through evaporation, determine the weight of crystals obtained. Solubility of barium chloride at $100\backslash$deg C is $59\mathrm{.}4$ g per $100$ g of water while at $20\backslash$deg C$,$ its solubility is$35\mathrm{.}8$ g per $100$ grams of water