2. MATHEMATICAL TOOLS I If Q = 4v3 + 3v2 , then the value of v' such that, there exist maxima of 'Q' - (A) O C) (D) none FIN N If y = sinx, then will be (A) cos x (B) sin x (C) - sin x (D) sin x + C Maximum value of f(x) = sinx + cosx is : ( A ) 1 (B) 2 The displacement of a body at any time t after starting is given by s = 15t - 0.41. The velocity of the body will be 7 ms' after time : (A) 20 s ( B ) 15 s (C) 10 s (D) 5 s LO A particle is moving in a straight line. Its displacement at time t is given by s (in m) = -413 + 2t, then its velocity and acceleration at time t = _ second are ( At - 2 m/s, - 8 m/s? ( B) 2 m/s, 6 m/s? (C) -2 m/s, 8 m/s ( D) 2 m/s, 8 m/s? A particle moves along a straight line such that its displacement at any time t is given by : s = 13 - 612 + 3t + 4 metres. The velocity when the acceleration is zero is : ( A ) 3 ms - 1 (B) - 12 ms-1 (C ) 42 ms - 1 (D) - 9 ms-1 M If x = ( 6y + 4 ) (3y2 + 4y + 3) then x dy will be : (A ) ( B) ( 3 y 2 + 4y + 3 )2 + c 3 y 2 + 4 y + 3 V (C) (3y2 + 4y + 3) (D) ( 6y + 4) ( 3 y 2 + 4y + 3 ) COMPREHENSION (18 to 20) : If charge flown through a cross section of wire in one direction during 0 to t is given by q = 3 sin (3t) then Find out the amount of charge flowing through the wire till t = It seconds. (A) 3 coulombs (B) 6 coulombs (C) 1 coulomb (D) Zero coulomb 19. Find out the current flowing through the wire at t = It second . (A) 4.5 Amp (B) 4.5 3 Amp (C) 3 12 Amp (D) 9 Amp. Find out the area under i - t curve from t = " to t = seconds : ( A ) 3 2 - 13 ( B ) 3 2 + 1 3 2 1 2 - 13 2 (D ) 2 + 13 21. The area of region between y = sinx and x-axis in the interval " will be : ( A ) 1 (B) O (C ) 2 (D ) Resonance Reg. & Corp. Office : CG Tower, A-46 & 52, IPIA, Near City Mall, Jhalawar Road, Kota (Raj.)-3240 Educating for better tomorrow Website : www.resonance. ac.in | E-mail : contact@resonance. ac.in Toll Free : 1800 258 5555 | CIN: U80302RJ2007PLC024029 PHYSICS IJSO VOL. 1