2. Mean = number of defects / NN= 10 ( given)Mean (x)= (1+3+2+1+4+1+2+0+3+1) = 18/10Mean=1.8Standard deviation:- ?1/N ( xi- mean)2SD = ?1/10 * ( (1-1.8)2 + (3-1.8)2 + (2-1.8)2+ (1-1.8)2+(4-1.8)2+ (1- 1.8)2 +(2-1.8)2+ (0-1.8)2+( 3-1.8)2+(1-1.8)2)SD= 1.16UCL= mean + Z*SDZ= 3 (given)UCL = 1.8 +3*1.16UCL= 5.28LCL= mean - Z*SDLCL = 1.8- 3*1.16LCL = - 1.68

Find the error in the above using below:

\fTo find the answer using the Excel formulas I provided in week 1, you would use the the Excel template for the P-Chart. Since the supervisor has selected a random sample of 20 rooms each over a ten-week period, you would have a sample size of 20, and number of samples of 10. Sample size 20 Number of samples 10 Average (p-bar) 0.09 Number Fraction Standard Sample Nonconforming Nonconforming Deviation LCLp CL UCLP 0.0500 0.063992 0 0.09 0.282 3 0.1500 0.063992 0.09 0.282 0.1000 0.063992 0 0.09 0.282 0.0500 0.063992 0 0.09 0.282 0.2000 0.063992 0 0.09 0.282 GOONAUAWNH 0.0500 0.063992 0 0.09 0.282 0.1000 0.063992 0.09 0.282 0.0000 0.063992 0 0.09 0.282 0.1500 0.063992 0 0.09 0.282 0.0500 0.063992 0 0.09 0.282