Question: 2 nemember the init function of Haskell? It can be defined in Haskell as: init :: [ a ] [ a ] init init (

2nemember the init function of Haskell? It can be defined in Haskell as:
init :: [a][a]
init
init (x:xs)=x : init xs
Formulate the appropriate Prolog rule init (xs,Ys) which is true if Ys is the initial part of Xs. That is, the query init ([1,2,3,4,5],[1,2,3,4]). would evaluate to true, or the query init ([1,2,3,4,5],Ys). would give Ys=[1,2,3,4].
Hint: this rule will be recursive, and will have a corresponding base case and recursive case, analogous to the base case and recursive case, respectively, of the above Haskell function - the main difference being that the Prolog rule init (xs,Yss) is a predicate, not a function.
 2nemember the init function of Haskell? It can be defined in

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