\"2 no Consider the series 8 = . 11:2}! {113 + $19!? To test 3 for convergence by a direct application of the integral test' one would calculate 24 i 7 (Fill in the corresponding integrand and the value of the improper integral, Enter a number if possible, or inf for so, -inf for 00, or div if no earlier input applies] n2 CK) According to the Integral Test, the series S = Z ":24 [n3 + (5)9132 (g A. converges Q B. diverges