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2. The length of stay in a certain cancer Hospital were organized into a frequency distribution. The mean length of stay was 28 days, the
2. The length of stay in a certain cancer Hospital were organized into a frequency distribution. The mean length of stay was 28 days, the medial 25 days and modal length is 23 days. The standard deviation was computed to be 4.2 days.
a) Is the distribution symmetrical, or skewed? Explain.(5 marks)
b) Calculate the Karl Pearson's coefficient of Skewness and interpret.
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a The distribution is skewed not symmetrical Heres why The mean length of stay 28 days is g...Get Instant Access to Expert-Tailored Solutions
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