2] This question is related to ionic bonding, The electron affinity ofan atom is the energy by which the negatiye ion {one additional electron] is lower than the neutral atom. \"Lower\" means that the neutral atom attracts an additional electron and binds it! This is because although the total charge of the neutral atom is zero, it is not zero eyerywhere in space. So there is some net attraction for the extra electron. This question helps you think about how that works for a threedimensional hydrogen atom. The is state of an electron on a hydrogen atom has a wayefunction on = 1 .9"foEl with on = H.529}: the Bohr radius. The charge density is e|ql)15|2. Then the electron charge contained within a sphere of radius R is (JG?) 2 e[1 e'zxfhrz + 2x + 1)], with x = R1110. a} Adding to this the nuclear charge +e at the origin giyes the total charge. Make a plot of this total charge enclosed in a sphere of radius R as a function ofx = R1110. t what yalue ofx does the total enclosed charge Qenmged drop below ey'E ? b} Gauss' law says that the electric flux through the surface of these spheres ie equal to chmgdg'eg. For this geometry, the electric flux through the surface is 4HR2E, where E is the stag] electric field. Make a plot of as a function of x = Rfo. This electric field attacts the E and additional electron that will form the negatiye ion. Here Em\" = is the electric field a 4:110:15 distance on from the bare hydrogen nucleus alone. c} The electric potential is related to the electric field as VIP.) 2 I: E(R)oiR.This is the area under the curye in b} between infinity and R. You can use your plotting program to eyaluate this, or do it analytically. Make a plot of folrmdfo) as a function of x, and on the same graph a plot of the normalized bare nuclear potential 3 {Dilution} as a function of x. Here 41150}? E is the electric potential due to the hydrogen nucleus alone a distance {10. Vnuclkao) : 41:50:10