2. We have learned molar G change due to formation of a regular solution is Gmmix=Gmmix,ideal+Gme=RT(xAlnA+xBlnB), molar G change due to formation of an ideal solution is Gmmixx,ideal=RT(xAlnxA+xBlnxB), the excess molar G change is Gme=GmmixGmmix,ideal=RT[xAln(A/xA)+xBln(B/xB)]=RT(xAlnA+xBlnB) . We also learned the partial molar G change of component A due to the formation of a regular solution is GAmix=RTlnA=RTlnA+RTlnxA Think what is the partial excess molar G change of component A in a solution GAe. The liquid Fe-Mn alloy at 1863K is a regular solution. Its excess molar G is 703J when xMn=0.2. a) Calda bate GMne and at xMn=0.6; b) calculate molar G change due to formation of Fe-Mn solution at xMn=0.4; Draw molar G change (due to mixing)-composition diagram using any software or method that you are familiar with. c) calculate the partial pressures of Mn and Fe exerted by the alloy at xMn=0.2. Find relevant information in the appendix of the textbook if needed