2. Which sequence of rigid motions will definitely work to take triangle GHJ onto triangle STU? A A. Rotate GHJ using center G until GH is lined up with ST and then reflect over aline halfway between G'H'J' and STU. B. Translate GHJ by the directed line segment GS. Rotate GHJ using S as the center by angle HST. Reflect GH over ST. C. Translate GHJ by the directed line segment GT. Rotate GH) using T as the center by angle HTS. Reflect G'H' over ST. D. Translate GHJ by the directed line segment GS.Translate GH by the directed line segment H'T. Translate G"H")" by the directed line segment/"T. 3. Reflect triangle STU across line ST. Which of these is a valid reason why the image of U will coincide with J? A. The image of U and J are on the same side of ST and make the same angle with it at T. B. The image of U and/ are the same distance along the same ray from T. C. The image of U and will not coincide after reflection over ST. D.Line ST is the perpendicular bisector of the segment connecting U and J, because the perpendicular bisector is determined by 2 points that are both equidistant from the endpoints of a segment. 2019 by Illustrative Mathematics NAME 4. Here is parallelogram ABCD: A DATE M B iM Mustrative Mathematics PERIOD 2