Question: 2 y t 2 1 - 2 t - ( 2 - l n ( t 2 1 ) ) y ' = 0 y

2yt21-2t-(2-ln(t21))y'=0
y(5)=0 solve for the general solution and the partictular solution
2 y t 2 1 - 2 t - ( 2 - l n ( t 2 1 ) ) y ' = 0 y

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