2) You want to test for an association between smoking behavior (non-smoker, past smoker, current smoker) and gender (male or female) using a Chi-Square Test of Independence (a = 0.05). Pearson Chi-Square Likelihood Ratio Chi-Square Tests Value 3.171* 3.217 1.106 df 2 2 1 Asymptotic Significance (2-sided) 205 200 293 Linear-by-Linear Association N of Valid Cases 402 a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 17.76. a) What are your null and alternate hypotheses? b) What is the chi-square test statistic in the table above? c) What is the p-value for the chi square statistic? d) What is your interpretation for your hypothesis?