20. [2/6 Points] DETAILS PREVIOUS ANSWERS SCALCET9 4.9.075.MI.SA. MY NOTES ASK YOUR T This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A stone was dropped off a cliff and hit the ground with a speed of 152 ft/s. What is the height of the cliff? (Use 32 ft/s for the acceleration due to gravity.) Step 1 We know that s(t) = Lat + vit + so, where s(t) = 0 is ground level and the positive direction is up. In this 2 situation, we have a = -32 v -32 ft/s2, vo = 0 0 ft/s, and so = h, where h is the height of the cliff (in feet) that we wish to find. Step 2 We have s(t) = _at" + Vot + 50 = -16tz + h. Therefore, the velocity is the following. V(t) = s'(t ) = Submit Skip (you cannot come back)