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20:24 Wed 23 Mar . . . 16% course.work a course.work My Account Student Log Out 4.d 1 point(s) To check our assumptions when learning

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20:24 Wed 23 Mar . . . 16% course.work a course.work My Account Student Log Out 4.d 1 point(s) To check our assumptions when learning about 1-2, we have to produce plots. Here's a side-by-side boxplot of number of reviews by city: Boxplots of Number of Reviews by City 300 Number of Reviews 200 100 Los Angeles Manhattan City Based on the side-by-side plot, select the appropriate statement(s). O From the side-by-side boxplot, we can compare the two sample means and conclude that the sample mean number of reviews for AirBnb listings in Los Angeles is higher than the sample mean number of reviews for listings in Manhattan. O From the side-by-side boxplot, we are able to compare the overall range for the number of reviews per AirBnb listing across these two cities (Los Angeles versus Manhattan) and say that the overall range for the two samples is similar. O From the side-by-side boxplot, we are able to compare the two sample standard deviations and conclude that the standard deviation for the number of reviews per Airbnb listing across these two cities (Los Angeles versus Manhattan) is similar. O From the side-by-side boxplot, we are able to compare the two sample IQRs and conclude that the IQR for the number of reviews per AirBnb listing across these two cities (Los Angeles versus Manhattan) is similar. 4.e 1 point(S) Based on the side-by-side boxplot provided in part d, which of the following is the appropriate t.test( ) output? O welch Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0542, df = 311.49, p-value = 0.04079 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 0. 7900966 36. 6968704 sample estimates: mean in group Los Angeles mean in group Manhattan 136. 2628 117 . 5193 O Welch Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0542, df = 311. 49, p-value = 0. 0204 alternative hypothesis: true difference in means is greater than 0 95 percent confidence interval: 3. 690299 Inf sample estimates: mean in group Los Angeles mean in group Manhattan 136. 2628 117 . 5193 O Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0737, df = 335, p-value = 0.03887 alternative means is not equal to 020123 Wed 23 Mar ?@16%l AA coursework I coursework a course .Work My Account Student Log Out C' Stats 250 W22 Required HW 7 prime Need Help 9 35 Points Possible Due: 3/25/22 11:59PM Last Auto-save: 3/23/22 8:13PM NOTICE: You have 23 unanswered parts. Please see the buttons outlined in red below. v1ewL|5T 2 unan- > Question 4 Background : Airbnb: Los Angeles versus Manhattan Airbnb is an online marketplace used by many travelers when booking lodging all over the world. The company serves as a broker, receiving commissions from each booking. Guests have the opportunity to give a review of their host once their lodging is complete. We randomly selected 337 Airbnb listings from two popular cities in the U.S. (Los Angeles and Manhattan) and recorded many variables including price per night (in dollars) and number of reviews (count). Using this data, we would like to assess if the population mean number of reviews for Airbnb listings in Los Angeles (group 1) is higher than the population mean number of reviews for Airbnb listings in Manhattan (group 2). The subquestions include R output that was generated using a data set called AianB which contains the following variables among others: (1) id = ID number for the 337 Airbnb listings in the study (2) city = city of the selected listing (Los Angeles / Manhattan) (3) price = price per night (in dollars) (4) number_of_reviews = number of reviews per listing Question 4 Subquestions 3': One variable in your data set is \"number_of_reviews = number of reviews per Airbnb listing". This variable is: point(s) I' C] a categorical variable. C] a quantitative variable. 3': Another variable in your data set is "city = city of the selected listing (Los Angeles / Manhattan)". This variable is: point(s) |" C] a categorical variable. C] a quantitative variable. finins) Which of the following plot(s) would you use to check the normality assumption. l' [j 00 Plot of number of reviews for the 337 AianBs in the data set 400 20:24 Wed 23 Mar . . . 16% course.work a course.work My Account Student Log Out C O From the side-by-side boxplot, we are able to compare the two sample IQRs and conclude that the IQR for the number of reviews per AirBnb listing across these two cities (Los Angeles versus Manhattan) is similar. 4.e 1 point(s) Based on the side-by-side boxplot provided in part d, which of the following is the appropriate t.test( ) output? O Welch Two Sample t-test data: AirBNB$number_of_reviews by AirBNBScity t = 2.0542, df = 311.49, p-value = 0.04079 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval : 0. 7900966 36. 6968704 sample estimates: mean in group Los Angeles mean in group Manhattan 136.2628 117 . 5193 O welch Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0542, df = 311. 49, p-value = 0. 0204 alternative hypothesis: true difference in means is greater than 0 95 percent confidence interval: 3. 690299 Inf sample estimates: mean in group Los Angeles mean in group Manhattan 136. 2628 117 . 5193 O Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0737, df = 335, p-value = 0.03887 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 0. 9638918 36. 5230752 sample estimates: mean in group Los Angeles mean in group Manhattan 136. 2628 117 . 5193 O Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0737, df = 335, p-value = 0. 01943 alternative hypothesis: true difference in means is greater than 0 95 percent confidence interval: 3. 835059 Inf sample estimates: mean in group Los Angeles mean in group Manhattan 136. 2628 117 . 5193 4.f 1 point(s) Select the appropriate evaluation of the p-value and corresponding conclusion. After evaluating the p-value, we do not have enough evidence against Ho and in support of Ha. Based on this data, we do not have enough evidence to suggest that on average the number of reviews for all AirBnB listings in Los Angeles is20:25 Wed 23 Mar . . @ 16% course.work a course.work My Account Student Log Out Two Sample t-test data: AirBNB$number_of_reviews by AirBNBScity t = 2.0737, df = 335, p-value = 0.03887 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 0. 9638918 36. 5230752 sample estimates: mean in group Los Angeles mean in group Manhattan 136.2628 117 . 5193 O Two Sample t-test data: AirBNB$number_of_reviews by AirBNB$city t = 2.0737, df = 335, p-value = 0.01943 alternative hypothesis: true difference in means is greater than 0 95 percent confidence interval: 3. 835059 Inf sample estimates: mean in group Los Angeles mean in group Manhattan 136.2628 117 . 5193 4.f 1 point(s) Select the appropriate evaluation of the p-value and corresponding conclusion. O After evaluating the p-value, we do not have enough evidence against Ho and in support of Ha- Based on this data, we do not have enough evidence to suggest that, on average, the number of reviews for all AirBnB listings in Los Angeles is higher than that of Manhattan. O After evaluating the p-value, we have some evidence against Ho and in support of Ha. Based on this data, we have some evidence to suggest that, on average, the number of reviews for all AirBnB listings in Los Angeles is higher than that of Manhattan. O After evaluating the p-value, we have strong evidence against Ho and in support of Ha. Based on this data, we have strong evidence to suggest that, on average, the number of reviews for all AirBnB listings in Los Angeles is higher than that of Manhattan. O After evaluating the p-value, we have very strong evidence against Ho and in support of Ha. Based on this data, we have very strong evidence to suggest that, on average, the number of reviews for all AirBnB listings in Los Angeles is higher than that of Manhattan. 4.g Provide an interpretation of the p-value in context. TBD points BIUXXX : Q V Font Size No answer entered. Click above to enter an answer. Saved Previous ~ Top Next > Save Assignment erms and Conditions Copyright @ 2015-201920124 Wed 23 Mar coursework 4.c 'I point(s) ?16%| coursework My Account Student Which of the following plot(s) would you use to check the normality assumption. O Sample Quantiles Frequency Sample Quantiles 200 300 400 100 40 60 80 100 20 200 300 400 100 GO Plot of number of reviews for the 337 AianBs in the data set 3 2 -1 O 1 2 3 Theoretical Quantiles Histogram of number of reviews for the 337 AianBs in the data set 0 100 200 300 400 Number of reviews 00 Plot of number of reviews for the 156 AianBs in Los Angeles Log Out C" 20:24 Wed 23 Mar . . . 16% course.work a course.work My Account Student Log Out C O 100 200 300 400 Number of reviews O QQ Plot of number of reviews for the 156 AirBnBs in Los Angeles 400 300 Sample Quantiles 200 100 O O -2 -1 2 Theoretical Quantiles O Histogram of number of reviews for the 181 AirBnBs in Manhattan 30 Frequency 20 10 O 100 200 300 400 Number of reviews 4.d point(s) To check our assumptions when learning about 1-H2, we have to produce plots. Here's a side-by-side boxplot of number of reviews by city: IN Boxplots of Number of Reviews by City 300 200 Number of Reviews 100 Los Angeles

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